请大神吗帮忙解决一个正则问题。

172.16.0.1 - - [22/Aug/2016:07:50:16 -0400] "GET /noindex/css/fonts/Light/OpenSans-Light.ttf HTTP/1.1" 404 240 "http://172.16.0.119/noindex/css/open-sans.css" "Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/52.0.2743.116 Safari/537.36"


日志分析，请问下如何用re正则匹配到 前边的IP（172.16.0.1） 和 后边 /noindex/css/fonts/Light/OpenSans-Light.ttf HTTP/1.1 和 Mozilla/5.0 (Windows NT 10.0; WOW64)


如何让以上三个地方匹配到。请大神们帮下忙

c = '''172.16.0.1 - - [22/Aug/2016:07:50:16 -0400] "GET /noindex/css/fonts/Light/OpenSans-Light.ttf HTTP/1.1" 404 240 "http://172.16.0.119/noindex/css/open-sans.css" "Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/52.0.2743.116 Safari/537.36"'''

rex = re.compile(r'(.*?) - -.*?] "(.*?) HTTP.*?" "(.*?)"')
print re.findall(rex, c)                                 
[('172.16.0.1', 'GET /noindex/css/fonts/Light/OpenSans-Light.ttf', 'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/52.0.2743.116 Safari/537.36')]

我在楼上@白玮炜 的基础上改了下， 匹配更精确， 更符合你的要求
import re
c = '''172.16.0.1 - - [22/Aug/2016:07:50:16 -0400] "GET /noindex/css/fonts/Light/OpenSans-Light.ttf HTTP/1.1" 404 240 "http://172.16.0.119/noindex/css/open-sans.css" "Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/52.0.2743.116 Safari/537.36"'''

rex = re.compile(r'([\d\.]+) - - \[.*\] "GET (.* HTTP/1\.1)".*?" "(.*?\))')
print re.findall(rex, c)

结果：
[('172.16.0.1', '/noindex/css/fonts/Light/OpenSans-Light.ttf HTTP/1.1', 'Mozilla/5.0 (Windows NT 10.0; WOW64)')]