a=['ibm', 1, 0, 'ibm', 1, 2, 'ibm', 3, 4, 'ibm', 5, 6, 'ibm', 7, 8, 'ibm', 9, 10, 'ibm', 11, 12, 'ibm', 13, 14, 'ibm', 15, 16, 'ibm', 17, 18, 'ibm', 19, 20, 'ibm', 21, 22, 'ibm', 23, 24, 'ibm', 25, 26, 'ibm', 27, 28, 'ibm', 29, 30, 'ibm', 31, 32, 'ibm', 33, 34, 'ibm', 35, 36, 'ibm', 37, 38, 'ibm', 39, 40, 'ibm', 41, 42, 'ibm', 43, 44, 'ibm', 45, 46, 'ibm', 47, 48, 'ibm', 49, 50, 'ibm', 51, 52, 'ibm', 53, 54, 'ibm', 55, 56, 'ibm', 57, 58, 'ibm', 59, 60, 'ibm', 61, 62, 'ibm', 63, 64, 'ibm', 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 96, 97, 98, 99]
我想列出所有的ibm字符串的索引值。
请问有什么办法吗？
菜鸟一枚，正在学习python的路上，请求指点
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