请问怎么对嵌套字典的列表的内容求和

有两个嵌套字典的列表，格式和长度相同，请问怎么对其中的内容求和

例如
[{'a': '1.0', 'b': '2.0', 'c': '3.0'}, {'a': '4.0', 'b': '5.0', 'c': '6.0'}]
[{'a': '7.0', 'b': '8.0', 'c': '9.0'}, {'a': '10.0', 'b': '11.0', 'c': '12.0'}]
变成
[{'a': '8.0', 'b': '10.0', 'c': '12.0'}, {'a': '14.0', 'b': '16.0', 'c': '18.0'}]

谢谢！

from collecti** import Counter
list1=[{'a': '1.0', 'b': '2.0', 'c': '3.0'}, {'a': '4.0', 'b': '5.0', 'c': '6.0'}]
list2=[{'a': '7.0', 'b': '8.0', 'c': '9.0'}, {'a': '10.0', 'b': '11.0', 'c': '12.0'}]
def transt(lis):
    for sub in lis:
        for key in sub:
            if isinstance(sub[key],str):
                sub[key]=float(sub[key])
            else:
                sub[key]=str(sub[key])
transt(list1)
transt(list2)
list3=[dict(Counter(list1[0])+Counter(list2[0])),dict(Counter(list1[1])+Counter(list2[1] )]
transt(list3)

1. a = [{'a': '1.0', 'b': '2.0', 'c': '3.0'}, {'a': '4.0', 'b': '5.0', 'c': '6.0'}]
   
2. b = [{'a': '7.0', 'b': '8.0', 'c': '9.0'}, {'a': '10.0', 'b': '11.0', 'c': '12.0'}]
   
3. c = []
   
4. for i in range(len(a)):
   
5.     key = list(a[i].keys())
   
6.     val1 = list(a[i].values())
   
7.     val2 = list(b[i].values())
   
8.     val3 = [eval(''.join(val1[j]+'+'+val2[j])) for j in range(len(val1))]
   
9.     dic = {}
   
10.     for j in range(len(key)): dic[key[j]] = val3[j]
    
11.     c.append(dic)
    
12. print(c)

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