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import random
def conflict(state,nextx):
nexty = len(state)
for i in range(nexty):
if abs(state[i]-nextx) in (0,nexty-i):
return True
return False
def queens(num=8,state=()):
for pos in range(num):
if not conflict(state,pos):
if len(state) == num - 1:
yield (pos,)---------------------------------------------------------当前面三个（1,3,0）都满足，最后一行满足条件，比如为2时，返回的是(2,)就终止循环了，请问（2，）是怎么添加到元组中，变成（1,3,0，2）的？
else:
for result in queens(num,state + (pos,)):
yield (pos,) + result
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