选修课作业，求大神帮忙

要求都在这里了！

先用lower方法全部转化为小写，然后使用标准库collection s里的Counter函数不就可以达到要求了么

1. #!/usr/bin/env python
   
2. # coding:utf-8
   
3. 
   
4. def charcount(text):
   
5.     t = text.lower()
   
6.     d= {}
   
7.     for i in t:
   
8.         d[i]=0
   
9.         for c in t:
   
10.             if i == c:
    
11.                 d[i]+=1
    
12.     return d
    
13. 
    
14. s = 'fdsafghfdgBFHJJHNvfwaFDFDFDFDSAFDSFAFSDDFSAFWEFDnvcbvqrewvFSSAfd432432423'
    
15. 
    
16. print charcount(s)
    
17. >>> ================================ RESTART ================================
    
18. >>>
    
19. {'a': 6, 'c': 1, 'b': 2, 'e': 2, 'd': 11, 'g': 2, 'f': 17, 'h': 3, 'j': 2, '3': 3, 'n': 2, 'q': 1, 's': 7, 'r': 1, '4': 3, 'w': 3, 'v': 4, '2': 3}

复制代码

t = input("请输入：").lower()
d = {}
for i in t:
    d = t.count(i)
print(d)

1. message='TANGGUOGUANLIhaoduoyanse'.lower()
   
2. count={}
   
3. for i in message:
   
4.     count.setdefault(i,0)
   
5.     count[i]+=1
   
6. print(count)
   

复制代码

from collecti** import Counter
c = Counter()
t = 'adfafagadfADFADGADF'
for i in t.lower():
    c[i]=c[i]+1
print(c)

s = 'abcedsgsrgsserttff'
d = {i:s.count(i) for i in s}
print(d)

1. s = 'abcssdgsf'
   
2. d = {i:s.count(i) for i in s}
   
3. print(d)

复制代码

# -*- coding: utf-8 -*-

str = raw_input("请输入只包含字母的字符串：")

new_str = str.lower()
result = {}
for i in new_str:
    result[i] = new_str.count(i)
print result

import collecti** as col
class Count():
    def __init__(self,num):
        count = col.Counter(num)
        c = dict(count.most_common())
        self.num=c

co=Count('adskadjadasdjasjsadas')
print(co.num)
#{'a': 7, 'd': 5, 's': 5, 'j': 3, 'k': 1}  新人在这里请大家多多指教

这个非常简单，只需要一个内置函数。

from collecti** import Counter

str = input("请输入字符串").lower()

count = dict(Counter(str))