python实现扫描网站后台地址！

这个确实很实用啊，可以扫描网站后台地址，不要做坏事哦

1. #!/usr/bin/python
   
2. 
   
3. import sys,httplib
   
4. from optparse import OptionParser
   
5. usageString = "Usage: %prog [options] hostname"
   
6. parser = OptionParser(usage=usageString)
   
7. (opts,args) = parser.parse_args()
   
8. if len(args) < 1:
   
9.     parser.error("Hostname is required")
   
10. print __doc__
    
11. website = args[0]
    
12. #login path
    
13. dirs = ["admin","login","admin_index","admin/admin","admin/login","admin/index","admin/user"]
    
14. 
    
15. for line in dirs:
    
16.     conn = httplib.HTTPConnection(website)
    
17.     conn.request('GET','/'+line)
    
18.     r1 = conn.getresponse()
    
19.     if r1.status == 200 or r1.status == 301:
    
20.         print "********************************Lucky?*************************************"
    
21.     print website+'/'+line,r1.status,r1.reason
    
22.     conn.close()
    
23.     conn = httplib.HTTPConnection(website)
    
24.     conn.request('GET','/'+line+'.asp')
    
25.     r1 = conn.getresponse()
    
26.     if r1.status == 200 or r1.status == 301:
    
27.         print "********************************Lucky?*************************************"
    
28.     print website+'/'+line+'.asp',r1.status,r1.reason
    
29.     conn.close()
    
30.     conn = httplib.HTTPConnection(website)
    
31.     conn.request('GET','/'+line+'.php')
    
32.     r1 = conn.getresponse()
    
33.     if r1.status == 200 or r1.status == 301:
    
34.         print "********************************Lucky?*************************************"
    
35.     print website+'/'+line+'.php',r1.status,r1.reason
    
36.     conn.close()
    
37. f.close()
    

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楼主写的是哪个版本的啊

为什么是一丢乱码

lai8015 发表于 2016-11-3 11:05
为什么是一丢乱码

嗯，确实乱码了， 我已经修改了

发表于 2014-7-11 09:37:18   好久的帖子额

sqlfeng 发表于 2016-11-4 12:30
发表于 2014-7-11 09:37:18   好久的帖子额

时间久不代表不实用 {:8_225:}

2.7

能注释一下吗？看不懂。。